Lab Guide: 11-ap-centipetal-force
Video:
Post-reading question: You must comment on this post with your suggestion for how to determine the mass of the object moving in a circle. Your suggestion should tell what you think should be graphed and what the slope on your graph would represent. Your post will count as two reading quiz points.
Video Lectures for AP Physics 
Have y be Fc. x be v^2/r and find the slope which is mass
Fc/(v^2/r) equal mass. Fc represents the y and V^2/r represents x.
Set Fc as your x and have v^2/r as your y to get the slope of m
Figure out the slope which is the mass n y fc v^2/r.
-Areli
So what would you plot in x, and what would you plot in y?
Set Fc as your y and have v^2/r as your x. so the slope/mass is m=fc*r/v^2
Fc would be y and v^2/r is x and m is your slope
make M your slope and let x = v^2/r and y =fg
M is your slope, v^2/r for x and fc as your y.
-Juju
You would set Fc as your x axis and have v^2/r as your y axis in order to get the slope of m.
fc as your y maybe and v^2/r as x to get slope
Fc on the Yaxis and v^2/r on the Xaxis and the slope should be the mass
Set Fc as your y and v^2/r as your x
Centripetal force on the y-axis, while having V^2/r on the x-axis. the slope of the curve should give you the mass.
I would graph Fc versus v^2/r
Since we are dealing with an object moving in a circular motion we will use Fnet=mv^2/r
and m would be your slope and v^2r will be your y-intercept.
Centripetal force as x and y as v^2/r, the slope would then be m
-Juan