Post-reading question: You must comment on this post with your suggestion for how to determine the mass of the object moving in a circle. Your suggestion should tell what you think should be graphed and what the slope on your graph would represent. Your post will count as two reading quiz points.

Have y be Fc. x be v^2/r and find the slope which is mass

Fc/(v^2/r) equal mass. Fc represents the y and V^2/r represents x.

Set Fc as your x and have v^2/r as your y to get the slope of m

Figure out the slope which is the mass n y fc v^2/r.

-Areli

So what would you plot in x, and what would you plot in y?

Set Fc as your y and have v^2/r as your x. so the slope/mass is m=fc*r/v^2

Fc would be y and v^2/r is x and m is your slope

make M your slope and let x = v^2/r and y =fg

M is your slope, v^2/r for x and fc as your y.

-Juju

You would set Fc as your x axis and have v^2/r as your y axis in order to get the slope of m.

fc as your y maybe and v^2/r as x to get slope

Fc on the Yaxis and v^2/r on the Xaxis and the slope should be the mass

Set Fc as your y and v^2/r as your x

Centripetal force on the y-axis, while having V^2/r on the x-axis. the slope of the curve should give you the mass.

I would graph Fc versus v^2/r

Since we are dealing with an object moving in a circular motion we will use Fnet=mv^2/r

and m would be your slope and v^2r will be your y-intercept.

Centripetal force as x and y as v^2/r, the slope would then be m

-Juan