4.2 Centripetal Force Lab (Linearizing a Graph)

Lab Guide: 11-ap-centipetal-force

Video:

Post-reading question: You must comment on this post with your suggestion for how to determine the mass of the object moving in a circle.  Your suggestion should tell what you think should be graphed and what the slope on your graph would represent.  Your post will count as two reading quiz points.

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17 Responses to 4.2 Centripetal Force Lab (Linearizing a Graph)

  1. Oscar says:

    Have y be Fc. x be v^2/r and find the slope which is mass

  2. Edgar Jimenez says:

    Fc/(v^2/r) equal mass. Fc represents the y and V^2/r represents x.

  3. Annabel M says:

    Set Fc as your x and have v^2/r as your y to get the slope of m

  4. Areli G says:

    Figure out the slope which is the mass n y fc v^2/r.
    -Areli

  5. Christian Larreynaga says:

    Set Fc as your y and have v^2/r as your x. so the slope/mass is m=fc*r/v^2

  6. Patricio says:

    Fc would be y and v^2/r is x and m is your slope

  7. Gabby says:

    make M your slope and let x = v^2/r and y =fg

  8. Daniela Felix says:

    You would set Fc as your x axis and have v^2/r as your y axis in order to get the slope of m.

  9. ashley vera says:

    fc as your y maybe and v^2/r as x to get slope

  10. Samuel M says:

    Fc on the Yaxis and v^2/r on the Xaxis and the slope should be the mass

  11. Aarón says:

    Set Fc as your y and v^2/r as your x

  12. Fernando E says:

    Centripetal force on the y-axis, while having V^2/r on the x-axis. the slope of the curve should give you the mass.

  13. Quinton Hal says:

    I would graph Fc versus v^2/r

  14. Adelene Miranda says:

    Since we are dealing with an object moving in a circular motion we will use Fnet=mv^2/r
    and m would be your slope and v^2r will be your y-intercept.

  15. Juan says:

    Centripetal force as x and y as v^2/r, the slope would then be m
    -Juan

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